## 8. Two numbers are such that the ratio between them is 3:5. If each is increased by 10, the ratio between the new numbers so formed is

Question

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## Answers ( )

Answer:Step-by-step explanation:Given The ratio of the 2 no. is = 3:5

Let the no. be 3x and 5x

If each one is increased by 10

They wil become = 3x + 10 and 5x + 10

A/Q,

3x + 10 / 5x + 10 = 5 / 7

7 ( 3x + 10) = 5 ( 5x + 10)

21x + 70 = 25x + 50

21x – 25x = 50 – 70

– 4x = -20

x = 20 / 4

So, x = 5

Now,

The no. are =3x

= 3 × 5

= 15

And

5x

= 5 × 5

= 25

ratios of numbers = 3 : 5let the constant ratios be xratios now become = 3x : 5xafter adding 10 to both the rational sides ==>3x + 10 : 5x + 10 = 5x : 7xlet the ratios be put in fractional form.3x + 10=5x5x + 10 = 7xcross multiplication7x ( 3x + 10 ) = 5x ( 5x + 10 )=> 21x^2 + 70x = 25x^2 + 50x=> 21x^2 – 25x^2 = 50x – 70x=> -4x^2 = -20x=> 4x^2 = 20x=> x^2 = 20x/4=> x^2 = 5x=> x * x = 5 * x=> x = 5number 1 = 3x = 3 * 5 = 15number 2 = 5x = 5 * 5 = 25pls mark as brainliest if you are satisfied