6. A ball dropped freely takes 0.2s to travel the last 6m distance before hitting the ground. Total time of fall is (g=10ms−2):

Question

6. A ball dropped freely takes 0.2s to travel the last 6m distance before hitting the ground. Total time of fall is (g=10ms−2):

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Rylee 2 weeks 2021-11-15T05:05:37+00:00 2 Answers 0 views 0

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    0
    2021-11-15T05:06:43+00:00

    Answer:

    Step-by-step explanation:

    For last 6m distance travelled , s=6m

    time=0.2s

    initial velocity=?

    a=g=9.8m/s2

    s=ut+1/2at²

    =6=u(0.2)+1/2 x 9.8 x0.2×0.2

    6=0.2 u + 4.9 x 0.04

    u=5.8/0.2

    u=29m/s

    For distance x, u=0m/s

    v=29m/s [ because initial velocity will be final]

    a=g=9.8m/s2

    s= v²-u²/2a

    =29²-0²/2×9.8

    =29×29/19.6

    s=42.5m

    Total distance=42.5 +6=48.5 m

    0
    2021-11-15T05:06:48+00:00

    Answer:

    For last 6m distance travelled, s=6m

    Time =0.2s

    Initial velocity =??

    a=g=9.8m/s ^2

    S=ut+1/2at^2

    =6=u(0.2)+1/2×9.8×0.2×0.2

    6=0.2u+4.9×0.04

    U=5.8/0.2

    U=29m/s

    For distance x, u=0m/s

    V=29m/s

    S=v^2-u^2/2as

    29^2-0^2/2×9.8

    S=42.5m

    Total distance= 42.5+6

    =48.5 m

    Step-by-step explanation:

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