5. A man is 3 times as old as his son. After 15 years, he will be only twice as old as his son. find their present age present ages.

Question

5. A man is 3 times as old as his son. After 15 years, he will be only twice as old as his son. find their present age
present ages.

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Camila 5 days 2021-10-08T22:00:02+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-08T22:01:55+00:00

    Answer:

    Present age of son = 15 years

    Present age of father = 45 years

    Step-by-step explanation:

    Let,

    Present age of son = x

    Present age of father = 3x

    After 15 years,

    The age of son = x + 15

    The age of father = 3x + 15

    ➨ 3x + 15 = 2(x + 15)

    ➨ 3x + 15 = 2x + 30

    ➨ 3x – 2x = 30 – 15

    ➨ 1x = 15

    ➨ x = 15 years

    Present age of son = 15 years

    Present age of father = 3x

    ➨ 3 (15)

    ➨ 3 × 15

    ➨ 45

    Present age of father = 45 years

    0
    2021-10-08T22:01:55+00:00

    Answer:

    let man’s age be x years and his sons age be t years

    A.T.P.

    x=3y

    after 15 years=> x+15=2 (y+15)

    x+15=2y+30

    put x=3y in above

    3y+15=2y+30

    3y-2y=30-15

    •°• y=15

    put y in x=3y

    x=3 (15)

    x=45

    man’s age=45 years

    son’s age=15 years

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