(√3-√2)(2√3-3√2) = ( 2√3-3√2)- (2√3-3√2) = √3×2√3 – √3×3√2 – √2×2√3 + √2×3√2 = – 3√6-2√6+3 x 2 =6-5√6+6 = 5√6

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(√3-√2)(2√3-3√2) = ( 2√3-3√2)- (2√3-3√2) = √3×2√3 – √3×3√2 – √2×2√3 + √2×3√2 = – 3√6-2√6+3 x 2 =6-5√6+6 = 5√6

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Lydia 2 months 2021-12-03T04:26:14+00:00 1 Answer 0 views 0

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    2021-12-03T04:27:36+00:00

    In valid format

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    Sorry but i need points

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