20. A welfare association collected ₹ 202500 as donation from residents of a colony. If each paid as many rupees as there were residents, fi

Question

20. A welfare association collected ₹ 202500 as donation from residents of a colony. If each paid as many rupees as there were residents, find the numbers of residents.
AND
21. The area of a square fields is 5184 m². A rectangular field, whose length is twice of its breadth has its perimeter equal to the perimeter of the square field. Find the area to the rectangular field.

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Margaret 3 months 2021-11-06T18:36:04+00:00 1 Answer 0 views 0

Answers ( )

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    2021-11-06T18:37:44+00:00

    Answer:

    Step-by-step explanation:

    20. Let the number of residents be x.

    Therefore, According to question x people donated x rupees. So equation formed will be –

    x × x = 202500

    or, x² = 202500

    or, ✓x² = ✓202500

    or, x = 450

    Answer ) There were 450 residents and each one of them paid 450 rupees for donation.

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    21.The area of a square field = 5184m^2

    The side of square field =

    = side × side = area ( area = 5184m^2)

    = area = 2 side

    = 5184 = 2side

    = 5184 / 2 = side

    = side = 2592 ( Is the side of square field)

    The perimeter of square field =

    = 4×side

    = 4× 2592

    = 10368 ( ans )

    According to the question

    perimeter of the square field = perimeter of the rectangular field.

    So the perimeter of rectangular field is= 10368m

    let the breadth of rectangular field be x.

    length = 2x

    the perimeter of rectangular field =

    = 2 × ( L + B ) = perimeter

    = 2× ( 2x + x ) = 10368

    = 2 × 3x = 10368

    = 3x = 10368/2

    = 3x = 5184

    = x = 5184 /3

    = x = 1728

    the breaDHt = x = 1728

    the length = 2x

    = 2× 1728

    =3456

    So the length is equal to 1728 and the length is equals to 3456.

    Area = length × breadth

    = 1728 × 3456

    = 5971968 ( ans )

    TAKE CARE!!

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