20. A welfare association collected ₹ 202500 as donation from residents of a colony. If each paid as many rupees as there were residents, fi

Question

20. A welfare association collected ₹ 202500 as donation from residents of a colony. If each paid as many rupees as there were residents, find the numbers of residents.
AND
21. The area of a square fields is 5184 m². A rectangular field, whose length is twice of its breadth has its perimeter equal to the perimeter of the square field. Find the area to the rectangular field.

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3 months 2021-11-06T18:36:04+00:00 1 Answer 0 views 0

Step-by-step explanation:

20. Let the number of residents be x.

Therefore, According to question x people donated x rupees. So equation formed will be –

x × x = 202500

or, x² = 202500

or, ✓x² = ✓202500

or, x = 450

Answer ) There were 450 residents and each one of them paid 450 rupees for donation.

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21.The area of a square field = 5184m^2

The side of square field =

= side × side = area ( area = 5184m^2)

= area = 2 side

= 5184 = 2side

= 5184 / 2 = side

= side = 2592 ( Is the side of square field)

The perimeter of square field =

= 4×side

= 4× 2592

= 10368 ( ans )

According to the question

perimeter of the square field = perimeter of the rectangular field.

So the perimeter of rectangular field is= 10368m

let the breadth of rectangular field be x.

length = 2x

the perimeter of rectangular field =

= 2 × ( L + B ) = perimeter

= 2× ( 2x + x ) = 10368

= 2 × 3x = 10368

= 3x = 10368/2

= 3x = 5184

= x = 5184 /3

= x = 1728

the breaDHt = x = 1728

the length = 2x

= 2× 1728

=3456

So the length is equal to 1728 and the length is equals to 3456.