13 sin A = 5 and A is an acute then find the value of 5sin A -2cos A divide by tan A Question 13 sin A = 5 and A is an acute then find the value of 5sin A -2cos A divide by tan A in progress 0 Math Skylar 4 days 2021-10-10T05:53:32+00:00 2021-10-10T05:53:32+00:00 2 Answers 0 views 0

## Answers ( )

Answer:–13 sinA = 5

sinA = 5/13 = p/h

Here,

Base = √ h² – p²

→ √ (13)² – (5)²

→ √ 169 – 25

→ √144

→

12unitscosA = b/h = 12/13

tanA = p/b = 5/12

• 5sinA – 2cosA/tanA

→ 5 (5/13) – 2(144/65)

→ 25/13 – 288/65

→ (125 – 288)/65

→

–163/65Answer:12/65Step-by-step explanation:HEY there, see it is given that 13 sin A= 5 and it is a acute angle so we can say that the sides must be 12, 13, and 5( ∵pythagoran triplet)

SO, now sin A=5/13, cos A= 12/13 and tan A= 5/12

⇒{(5×5/13)-(2×12/13)}÷5/12

⇒(1/13)×12/5

⇒12/65

hope it helps