11. Each of equal sides of an isosceles triangle is 4 cm greater than its height. If the base of the triangle is 24 cm; calculate

Question

11. Each of equal sides of an isosceles triangle is
4 cm greater than its height. If the base of the
triangle is 24 cm; calculate the perimeter and
the area of the triangle.​

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1 week 2021-11-15T10:08:57+00:00 2 Answers 0 views 0

Answers ( )

  1. Charlotte
    0
    2021-11-15T10:10:08+00:00

    Answer:

    24 को 4 बराबर 66 x 4 = 24 से विभाजित किया गया है और यही उत्तर है जब आपको इस k के लिए समानांतर रेखाओं का उपयोग करना होगा

    24 ko 4 baraabar 66 x 4 = 24 se vibhaajit kiya gaya hai aur yahee uttar hai jab aapako is k ke lie samaanaantar rekhaon ka upayog karana hoga

    Step-by-step explanation:

  2. Charlotte
    0
    2021-11-15T10:10:40+00:00

    Answer:

    Perimeter = 64cm

    Area = 192cm^2

    Step-by-step explanation:

    Base = 24cm

    Height = xcm

    (x+4)^2 = x^2 + (12)^2

    x^2 + 8x + 16 = x^2 + (12)^2

    8x = x^2 – x^2 + 144 – 16

    8x = 128

    x = 128/8

    x = 16

    Perimeter = 24 + 16+ 4 + 16 + 4

    Perimeter = 64cm

    Area = \sqrt{s(s-a)(s-b)(s-c)}

    {S = 64/2 = 32 ; A = 24 ; B = 20 ; C = 20}

    Area = \sqrt{32(32-24)(32-20)(32-20)}

    Area = \sqrt{32*8*12*12}

    Area = \sqrt{8*4*8*12*12}

    Area = 8*2*12

    Area = 192cm^{2}

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