(11): AB is the diameter. TB is tangent to the circle. If Q is a point on TB. Then QA is equal to “a): VAB? +4QB2 (B): V4AB2

Question

(11): AB is the diameter. TB is tangent to the circle. If Q is a point on TB. Then QA is equal
to
“a): VAB? +4QB2
(B): V4AB2 + QB
(C): VAB2 +QB2
d): VAB2-QB2​

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Ariana 46 mins 2021-10-13T11:39:08+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-13T11:40:32+00:00

    Step-by-step explanation:

    From the given data , you can find the QA by applying Pythagoras theorem in it as ∠ABQ = 90 °.(The tangent is always perpendicular to the radius at the point of contact .)

    QA  = √(AB2+QB2)

    Hope this would have cleared your doubt .

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