## (11): AB is the diameter. TB is tangent to the circle. If Q is a point on TB. Then QA is equal to “a): VAB? +4QB2 (B): V4AB2

Question

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## Answers ( )

Step-by-step explanation:From the given data , you can find the QA by applying Pythagoras theorem in it as ∠ABQ = 90 °.(The tangent is always perpendicular to the radius at the point of contact .)

QA = √(AB2+QB2)

Hope this would have cleared your doubt .